Jika panjang AB = 8 cm dan BC = 2 cm. hitung besar momen gaya batang jika sistem diputar dengan poros dipusat massa (tengah batang)
Jawaban:
Fa = 20 N
Ra = ½ . 10 = 5 cm
τa = 20 . 5 = 100 cm.N (arah : searah jaum jam)
Fb = 10 N
Rb = 5 – 2 = 3 cm
τb = 10 . 3 = 30 cm.N
(arah: searah jarum jam)
Fc = 20 N
Rc = ½ . 10 = 5 cm
τc = 20 . 5 = 100 cm.N
(arah: seaah jarum jam)
Resultan momen gaya / torsi :
τ = 100 + 30 + 100 = 230 cm . N
= 2,3 m.N
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